I superficially assumed a <code>frozenset</code> accounts for the order of items it was constructed with such that the following assertion would fail.
<pre><code class="lang-bash">assert(
 frozenset([('a',1), ('b',1)]) == frozenset([('b',1), ('a',1)])
)
</code></pre>
Thinking about it for a second, sets are unordered, hence the above assertion holds.

I superficially assumed a `frozenset` accounts for the order of items it was constructed with such that the following assertion would fail.

```bash
assert(
   frozenset([('a',1), ('b',1)]) == frozenset([('b',1), ('a',1)])
)
```

Thinking about it for a second, sets are unordered, hence the above assertion holds.

Danny's blog

Danny's blog

frozen sets pay no heed to order